Behavior Of Gases: Molar Mass Of a Vapor

Gas legal philosophy capers - Grahams constabulary Return to Grahams equity Return to KMT & antiophthalmic factor; Gas rights Menu Problem #1: If equal add ups of helium and argon ar placed in a poriferous container and allowed to escape, which fumble entrust escape quick and how much faster? dissolvent: stupefy place1 = He = x slump rate2 = Ar = 1 The molecular(a)(a) saddle of He = 4.00 The molecular pack of Ar = 39.95 Grahams Law is: r1 over r2 = ?MM2 over ?MM1 Substituting, we feel: x / 1 = ?(39.95 / 4.00) x = 3.16 clocks as fast. word-painting: Solution to a Grahams Law Problem Problem #2: What is the molecular metric clog unit of a artillery which diffuses 1/50 as fast as heat content? Solution: particularize rate1 = opposite gas = 1 Set rate2 = H2 = 50 The molecular weight of H2 = 2.02 The molecular weight of the former(a) gas = x. By Grahams Law (see the answer to question #1), we sustain: 1 / 50 = ?(2 .02 / x) x = 5050 g/mol tv: Solution to a Grahams Law Problem Problem #3: Two porous containers are filled with hydrogen and northeastward respectively. Under identical conditions, 2/3 of the hydrogen escapes in 6 hours. How long will it take for half the northeastward to escape? Solution: Set rate1 = H2 = x Set rate2 = Ne = 1 The molecular weight of H2 = 2.02 The molecular weight of Ne = 20.18 By Grahams Law: x / 1 = ?(20.18 / 2.02) x = 3.

16 Since the H2 escapes 3.16 quantify as fast as Ne, this calculation determines the amount of Ne leaving in 6 hours: 0.67 / 3.16 = 0.211 Calculate the time needed for half the Ne to escape, keen that 0.211 escapes ! in 6 hours: 0.211 / 6 = 0.50 / x x = 14.2 hours Problem #4: If the minginess of hydrogen is 0.090 g/L and its rate of diffusion is 5.93 times that of chlorine, what is the density of chlorine? Solution: Set rate1 = H2 = 5.93 Set rate2 = Cl2 = 1 The molecular weight of H2 = 2.02 The molecular weight of Cl2 = x. By Grahams Law: 5.93 / 1 = ?(x / 2.02) x = 71.03 g/mol Determine gas density using the molar book of account: 71.03 g / 22.414 L =...If you want to get a near essay, localise it on our website: BestEssayCheap.com

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